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7r^2-53r-117=0
a = 7; b = -53; c = -117;
Δ = b2-4ac
Δ = -532-4·7·(-117)
Δ = 6085
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-53)-\sqrt{6085}}{2*7}=\frac{53-\sqrt{6085}}{14} $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-53)+\sqrt{6085}}{2*7}=\frac{53+\sqrt{6085}}{14} $
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